e^x+(x-3)e^x =[1+(x-3)]e^x =(x-2)e^x

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e^x+(x-3)e^x =[1+(x-3)]e^x =(x-2)e^x

e^x+(x-3)e^x =[1+(x-3)]e^x =(x-2)e^x
e^x+(x-3)e^x =[1+(x-3)]e^x =(x-2)e^x

e^x+(x-3)e^x =[1+(x-3)]e^x =(x-2)e^x
乘法结合律.ab+bc=(a+c)b

e^x+(x-3)e^x =[1+(x-3)]e^x =(x-2)e^x,求解释这步骤~~
e^x+(x-3)e^x (提公因式e^x得)=[1+(x-3)]e^x=(x-3+1)e^x= =(x-2)e^x