计算下列定积分SOS! (1)∫2→6 (x^2-1)dx (2)∫-1→1(x^3-3x^2)dx (3)1→27 dx/3根号x

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/15 13:35:03
计算下列定积分SOS! (1)∫2→6 (x^2-1)dx (2)∫-1→1(x^3-3x^2)dx (3)1→27 dx/3根号x

计算下列定积分SOS! (1)∫2→6 (x^2-1)dx (2)∫-1→1(x^3-3x^2)dx (3)1→27 dx/3根号x
计算下列定积分SOS! (1)∫2→6 (x^2-1)dx (2)∫-1→1(x^3-3x^2)dx (3)1→27 dx/3根号x

计算下列定积分SOS! (1)∫2→6 (x^2-1)dx (2)∫-1→1(x^3-3x^2)dx (3)1→27 dx/3根号x

如上图,祝好!

∫(2,6) (x² - 1) dx
= x³/3 - x |(2,6)
= (6³/3 - 6) - (2³/3 - 2)
= 196/3

∫(- 1,1) (x³ - 3x²) dx
= 0 - 3∫(- 1,1) x² dx
= - x³ |(- 1,1...

全部展开

∫(2,6) (x² - 1) dx
= x³/3 - x |(2,6)
= (6³/3 - 6) - (2³/3 - 2)
= 196/3

∫(- 1,1) (x³ - 3x²) dx
= 0 - 3∫(- 1,1) x² dx
= - x³ |(- 1,1)
= - (1 - (- 1))
= - 2

∫(1,27) dx/x^(1/3)
= ∫(1,27) x^(- 1/3) dx
= (3/2)x^(2/3) |(1,27)
= 27/2 - 3/2
= 12

收起