设{an}满足a1+3a2+.+3n-1an=n/3(n-1为次方),n属于N*,求{an}的通项公式.2.设bn=n/an,

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设{an}满足a1+3a2+.+3n-1an=n/3(n-1为次方),n属于N*,求{an}的通项公式.2.设bn=n/an,

设{an}满足a1+3a2+.+3n-1an=n/3(n-1为次方),n属于N*,求{an}的通项公式.2.设bn=n/an,
设{an}满足a1+3a2+.+3n-1an=n/3(n-1为次方),n属于N*,求{an}的通项公式.2.设bn=n/an,

设{an}满足a1+3a2+.+3n-1an=n/3(n-1为次方),n属于N*,求{an}的通项公式.2.设bn=n/an,
a1+3a2+.+3^(n-1)an=n/3 两边同乘以3得:3a1+9a2+……+3^nan=n.
n-1项是.3a1+9a2+……+3^(n-1)an-1=n-1.
两式想减得3^nan=1
an=3^(-n)

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