合并同类项2a-{-3b+[4a-(3a-b)]}

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合并同类项2a-{-3b+[4a-(3a-b)]}

合并同类项2a-{-3b+[4a-(3a-b)]}
合并同类项2a-{-3b+[4a-(3a-b)]}

合并同类项2a-{-3b+[4a-(3a-b)]}
先去掉括号,一层一层来.
原式子=2a-{-3b+[4a-3a+b]}
=2a-{-3b+[a+b]}
=2a-{-3b+a+b}
=2a-{a-2b}
=a+2b
所以最后同类项合并以后就是a+2b.

原式=2a-[-3b+(4a-3a+b)]
=2a-(-3b+a+b)
=2a+2b-a
=a+2b

2a-{-3b+[4a-(3a-b)]}
=2a-[-3b+4a-(3a-b)]
=2a-[-3b+4a-3a+b)]
=2a-[4a-3a+b-3b]
=2a-[a-2b]
=2a-a+2b
=a+2b
不懂的欢迎追问,如有帮助请采纳,谢谢!

2a-{-3b+[4a-(3a-b)]}
原式=2a-[-3b+4a-3a+b]
=2a-(a-2b)
=2a-a+2b
=a+2b

a+2b

2 a - {- 3 b + 【 4 a - (3 a - b)】}
= 2 a - {- 3 b + 4 a - 3 a + b }
= 2 a + 3 b - 4 a + 3 a - b
= a + 2 b

答案a+2b 先拆小括号再拆中括号最后大的

合并同类项2a-{-3b+[4a-(3a-b)]}
= 2a-{-3b+[4a-3a+b]}
= 2a-{-3b+4a-3a+b}
= 2a+3b-4a+3a-b
= 2b+a