化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 22:15:52
化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
sinα cosα=2/3 (sinα)^2 (cosα)^2=1 所以2sinαcosα=-5/9 (sinα-cosα)^2=1-(-5/9)=14/9又α∈(0,π),所以sinα-cosα=√14/3 sinα cosα=2/3 由以上两个方程解得 sinα=(2 √14)/6 cosα=(2-√14)/6
化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)=
化简sin^2(α-π/6)+sin^2(α+π/6)-sin^2α
sin(kπ+α)化简
2sin(α+π/3)=sinα+______
为什么sin(2π-α)=-sinα?
化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α)
化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)过程
化简sin(π/4+α)cosα-sin(π/4-α)sinα
化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α)
化简1-sin[α-2π]sin[π+α]-2sin²[-α].
化简:sin²α+sin²(α+π/3)+sin²(α-π/3)
sin(π-α)=-2sin(π/2+α),则sinαcosα等于
sin(π-α)=-2sin(π/2+α),求sinα·cosα
已知sin(3π-α)=-2sin(π/2+α)则sinαcosα
求sin^2α+sin^2(π/3 +α)+sin^2(π/3 -α)
求值sin^2(α-π/6)+sin^2(α+π/6)-sin^2α
化简 sin(π+α)+sin(2π+α)+sin(3π+α)+……+sin(kπ+α) k属于Z
化简:(sinα-cosα)^2+sin4α/2cos2α 化简:sin^2x+sin^2(x+2π/3)+sin^2(x-2π/3)