麻烦知道人士帮忙解决一下,万分感谢!在自然数1~100中找出10个不同的数,使这10个数的倒数和等于1提示:1/(1*2)=1-1/2 1/(2*3)=1/2-1/3 1/(3*4)=1/3-1/41=(1-1/2)+(1/2-1/3)+(1/3-1/4)+1/4
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/10 10:12:46
麻烦知道人士帮忙解决一下,万分感谢!在自然数1~100中找出10个不同的数,使这10个数的倒数和等于1提示:1/(1*2)=1-1/2 1/(2*3)=1/2-1/3 1/(3*4)=1/3-1/41=(1-1/2)+(1/2-1/3)+(1/3-1/4)+1/4
麻烦知道人士帮忙解决一下,万分感谢!在自然数1~100中找出10个不同的数,使这10个数的倒数和等于1
提示:1/(1*2)=1-1/2 1/(2*3)=1/2-1/3 1/(3*4)=1/3-1/4
1=(1-1/2)+(1/2-1/3)+(1/3-1/4)+1/4
麻烦知道人士帮忙解决一下,万分感谢!在自然数1~100中找出10个不同的数,使这10个数的倒数和等于1提示:1/(1*2)=1-1/2 1/(2*3)=1/2-1/3 1/(3*4)=1/3-1/41=(1-1/2)+(1/2-1/3)+(1/3-1/4)+1/4
1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90+1/10
=1/(1×2)+1/(2×3)+1/(3×4)+1/(4×5)+1/(5×6)+1/(6×7)+1/(7×8)+1/(8×9)+1/(9×10)+1/10
=(1 - 1/2)+(1/2 - 1/3)+(1/3 - 1/4)+……+(1/9 - 1/10)+1/10
=1 - 1/10 +1/10
=1
11111111111111111111
2,6,12,20,30,42,56,72,90,10》这十个数
2,6,10,12,20,30,42,56,72,90
1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90+1/10
=1/2+1/(2*3)+1/(3*4)+1/(4*5)+1/(5*6)+1/(6*7)+1/(7*8)+1/(8*9)+1/(9*10)+1/10
=1/2+1/2(-1/3+1/3)+(-1/4+1/4)+(-1/5+1/5)+(-1/6+1/6)+(-1/7+1/7)+(-1/8+1/8)+(-1/9+1/9)+(-1/10+1/10)
=1/2+1/2=1
2 6 10 12 20 30 42 56 72 90