作业帮解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/05 22:21:28
解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
(1)sin2x-cos3x=0
sin2x-sin(π/2-3x)=0
2sin(π/4-x/2)cos(5x/2-π/4)=0
x/2-π/4=kπ或5x/2-π/4=kπ+π/2
x=2kπ+π/2或x=2kπ/5+3π/10
(2)sin(2x+π/3)=-sin(x-π/6)=sin(π/6-x)
2x+π/3=2kπ+π/6-x
x=2kπ/3-π/18
(3)tan(x+π/6)=-1=tan(-π/4)
x+π/6=kπ-π/4
x=kπ-5π/6
证 sin2x * cos3x =(1/2) * [sin5x + sin(-x)]
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解方程：(1)sin2x=cos3x (2)sin(2x+π/3)+sin(x-π/6)=0 (3)sin(x+π/6)+cos(x+π/6)=0
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