作业帮高一两题对数计算题求解答两题在这里,给个思路也可以
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/11 01:25:26
高一两题对数计算题求解答两题在这里,给个思路也可以
高一两题对数计算题求解答
两题在这里,给个思路也可以
高一两题对数计算题求解答两题在这里,给个思路也可以
[ (1-log6【3】)^2 + log6【2】* log6【18】] ÷log6【4】
= [ (log6【6】-log6【3】)^2 + log6【2】* log6【2*9】] ÷log6【2^2】
= [ (log6【6/3】)^2 + log6【2】* log6【18】] ÷ [2log6【2】]
= [ (log6【2】) + log6【18】] ÷ 2
= [ (log6【2*18】] ÷ 2
= [ (log6【6^2】] ÷ 2
= 2 ÷ 2
= 1
( log2【5】+ log4【125】)* log3【2】/ log√3【5】
= ( lg5 / lg2+ lg125 / lg4) * (lg2 / lg3)/ ( lg5 / lg√3)
= ( lg5 / lg2+ lg5^3 / lg2^2) * (lg2 / lg3)/ ( lg5 / lg√3)
= [ lg5 / lg2+ 3 lg5 / (2lg2)] * (lg2 / lg3)/ [lg5 / (1/2 lg3)]
= [2 lg5 + 3 lg5 / (2 lg2)] * (lg2 /(2 lg5)
= [5 lg5 / (2 lg2)] * (lg2 /(2 lg5)
= 5/2 * 1/2
= 5/4
1. [(1-log6 3)²+log6 2*log6 18]÷log6 4
=(1-2log6 3+log²6 3+log6 2*(log6 3+log6 6)]÷log6 4
=(1-2log6 3+log²6 3+log6 2*log6 3+log6 2)÷log6 4
=[1-2log6 3+log6 2+log6 3*(log6 3+...
全部展开
1. [(1-log6 3)²+log6 2*log6 18]÷log6 4
=(1-2log6 3+log²6 3+log6 2*(log6 3+log6 6)]÷log6 4
=(1-2log6 3+log²6 3+log6 2*log6 3+log6 2)÷log6 4
=[1-2log6 3+log6 2+log6 3*(log6 3+log6 2)]÷log6 4
=(log6 6-log6 3+log6 2)÷log6 4
=[log6 (6*2/3)]÷log6 4
=log6 4÷log6 4
=1
2. (log2 5+log4 125)*log3 2/log√3 5
=(log2 5+(3/2)log2 5)*log3 2/[2log3 5]
=(5/2)log2 5*(1/2)log5 2
=(5/4)*log2 5/log 2 5
=5/4
收起
自己算
已上图