已知正数a,b满足 1/a^2 +4/b^2

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已知正数a,b满足 1/a^2 +4/b^2

已知正数a,b满足 1/a^2 +4/b^2
已知正数a,b满足 1/a^2 +4/b^2

已知正数a,b满足 1/a^2 +4/b^2
正数a,b满足 a^2+2b^2=15 ,(改题了)
∴设a=√15cosu,b=√(15/2)sinu,0代入 1/a^2 +4/b^2 <=1 ,得
1/[15(cosu)^2]+4/[(15/2)(sinu)^2]<=1,
1/15+(1/15)(tanu)^2+8/15+(8/15)(cotu)^2<=1,
∴(tanu)^2+8(cotu)^2<=6,
∴(tanu)^4-6(tanu)^2+8<=0,
解得2<=(tanu)^2<=4,
∴√2<=tanu<=2,
∴arctan√2<=u<=arctan2,
∴a+b=√(45/2)sin[u+arctan(1/√2)],
arctan√2+arctan(1/√2)=π/2,
sin(arctan√2)=√(2/3),cos(arctan√2)=√(1/3),
sin(arctan2)=2/√5,cos(arctan2)=1/√5,
∴sin[arctan2+arctan(1/√2)]=(2√2+1)/√15,
∴a+b的取值范围是[(4√3+√6)/2,3√10/2].