数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56

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数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56

数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56
数学对书问题
log(2)3=a log(3)7=b 用a和b表示log(14)56

数学对书问题log(2)3=a log(3)7=b 用a和b表示log(14)56
a=lg3/lg2
b=lg7/lg3
a·b=lg7/lg2
log(14)56=lg56/lg14
=lg(7·2^3)/lg(7·2)
=(lg7+3lg2)/(lg7+lg2)
分子分母同时除以lg2得:lg7/lg2+3/lg7/lg2+1
即!a·b+3/a·b+1
(ab+3)/(ab+1)

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