“(1/4x1/6+1/6x1/8+1/8x1/10+1/10x1/12)x2的简便方法

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“(1/4x1/6+1/6x1/8+1/8x1/10+1/10x1/12)x2的简便方法

“(1/4x1/6+1/6x1/8+1/8x1/10+1/10x1/12)x2的简便方法
“(1/4x1/6+1/6x1/8+1/8x1/10+1/10x1/12)x2的简便方法

“(1/4x1/6+1/6x1/8+1/8x1/10+1/10x1/12)x2的简便方法
因为1/[n(n+2)]=1/2*[1/n-1/(n+2)]
所以1/4x1/6+1/6x1/8+1/8x1/10+1/10x1/12
=1/2*(1/4-1/6+1/6-1/8+1/8-1/10+1/10-1/12)
=1/2*(1/4-1/12)
=1/12
所以(1/4x1/6+1/6x1/8+1/8x1/10+1/10x1/12)x2=1/12*2=1/6