Pay attention to y=ax^2+bx+c(a≠0), and answer the question.If the two roots of this equation are m&n, which situation can be m0 orm>0, nNote: y=0 (I typed wrong.)

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Pay attention to y=ax^2+bx+c(a≠0), and answer the question.If the two roots of this equation are m&n, which situation can be m0 orm>0, nNote: y=0 (I typed wrong.)

Pay attention to y=ax^2+bx+c(a≠0), and answer the question.If the two roots of this equation are m&n, which situation can be m0 orm>0, nNote: y=0 (I typed wrong.)
Pay attention to y=ax^2+bx+c(a≠0), and answer the question.
If the two roots of this equation are m&n, which situation can be m0
or
m>0, n
Note: y=0 (I typed wrong.)

Pay attention to y=ax^2+bx+c(a≠0), and answer the question.If the two roots of this equation are m&n, which situation can be m0 orm>0, nNote: y=0 (I typed wrong.)
c/a<0

m*n<0 ==>
x1(2)=(1/2a)(-b+(-)(b^2-4ac)^(1/2))==>
x1*x2<0==>4ac<0==>ac<0

1.m<0, n>0 or m>0, n<0
2.mn<0
They are equivalent.
Note: c/a=mn.(Viète's formulas)
So...iff. c/a<0,then m<0, n>0 or m>0, n<0.
P.S."c/a<0" & "ac<0" are also equivalent.