作业帮1/2[cos(2x)cos(π/6)+sin(2x)sin(π/6)]-1/2[cos(2x)cos(π/6)-sin(2x)sin(π/6)]=1/2sin(2x)请问怎么化得1/2sin(2x)?
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 05:47:50
![1/2[cos(2x)cos(π/6)+sin(2x)sin(π/6)]-1/2[cos(2x)cos(π/6)-sin(2x)sin(π/6)]=1/2sin(2x)请问怎么化得1/2sin(2x)?](/uploads/image/z/6934337-17-7.jpg?t=1%2F2%5Bcos%282x%29cos%28%CF%80%2F6%29%2Bsin%282x%29sin%28%CF%80%2F6%29%5D-1%2F2%5Bcos%282x%29cos%28%CF%80%2F6%29-sin%282x%29sin%28%CF%80%2F6%29%5D%3D1%2F2sin%282x%29%E8%AF%B7%E9%97%AE%E6%80%8E%E4%B9%88%E5%8C%96%E5%BE%971%2F2sin%282x%29%3F)
1/2[cos(2x)cos(π/6)+sin(2x)sin(π/6)]-1/2[cos(2x)cos(π/6)-sin(2x)sin(π/6)]=1/2sin(2x)请问怎么化得1/2sin(2x)?
1/2[cos(2x)cos(π/6)+sin(2x)sin(π/6)]-1/2[cos(2x)cos(π/6)-sin(2x)sin(π/6)]=1/2sin(2x)
请问怎么化得1/2sin(2x)?
1/2[cos(2x)cos(π/6)+sin(2x)sin(π/6)]-1/2[cos(2x)cos(π/6)-sin(2x)sin(π/6)]=1/2sin(2x)请问怎么化得1/2sin(2x)?
前後两式提出1/2相减後结果为2sin(2x)sin(π/3)
sin(π/3)=1/2
所以结果为1/2sin(2x)