dy/dx=(x+y+1)/(x-y+1)的通解答案是e的arctg[y/(x+1)]次幂=c[(x+1)dy/dx=(x+y+1)/(x-y+1)的通解答案是e的arctg[y/(x+1)]次幂=c[(x+1)

dy/dx=1+1/(x-y) dy/dx=1-cos(y-x) dy/dx=x(1-y) dy/dx = 1/x-y dy/dx,y=(1+x+x^2)e^x 设y=（x/1-x)^x,求dy/dx dy/dx=x+y dy/dx=x(1+y^2)/y通解 已知y=x^(1/y),求dy/dx? dy/dx=(e^x+x)(1+y^2)通解 dy/dx=1/(x+y) 求解微分方程题目错了应该是dy/dx=y/(x+y) 求解微分方程 求微分方程y－dy／dx=1＋x×dy／dx的通解 y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy 微分方程通解（1+e^(x/y))dx+e^(x/y)(1-x/y)dy=0 (1-x)dx-(1+y)dy=0求通解 解微分方程(1+x)dy=(1+y)dx 解微分方程 dy/y+1=dx/x+1 (1-x)dx—(1+y)dy=0