求证:a^5+b^5>a^2b^3+a^3b^2

求证:a^5+b^5>a^2b^3+a^3b^2
求证:a^5+b^5>a^2b^3+a^3b^2
 

求证:a^5+b^5>a^2b^3+a^3b^2
a^5-a^2b^3+b^5-b^2a^3=a^2(a^3-b^3)+b^2(b^3-a^3)
=(a^2-b^2)*(a^3-b^3)
因为这2个式子符号相同 所以上式大于0