{ 2x+2y+10z=100 7x+4y+16z=200 7x+7y+30z=400,帮忙解一下,过程啊,急需!三元一次方程啊答案是x=8 y=12 z=6 某饮食方案中要求每天食谱中包含100单位的脂肪，200单位的蛋白质，400单位的淀粉。现有三种

x-y+z=10 x+y+z=4 4x+2y+z=7 解三元一次方程 x+y+z=10 x+y+z=4 x+2y+z=7 解三元一次方程 已知4x-3y-6z=0,x+2y-7z=0,求5x+2y-z/2x-3y-10z 已知,方程组:4x-3y-7z=0 x+2y=10z 则(x-y+z)÷(x+y+z)=—— 2x+z=10 x+y-z=4 3x-y-z=0 请高手帮我解几道3元1次的方程组!好的100分,x+2y+3z=15x-y+7z=20x+3y+2z=14x+y-z=3y+z-x=5z+x-y=7x+y-z=0.5x-3y+2z=03x+2y-z=23x-2y=12y+3z=2x+5z=315x-3y+2z=13x+4y-z=-18z=136x-y-z=32x-4y+8z=53x-6y-z=10x+y=3y+z=5x+z=6 (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 解方程 Y=X+Z Y-Z=2 100Z+10Y+X-(100X+10Y+Z)=99 Y=X+ZY-Z=2100Z+10Y+X-(100X+10Y+Z)=99 int x,y,z; x=2; y=4; z=7; x=y-- {2x+y=10 {x-y+z=4 {3x-y-z=0 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 解下列三元一次方程组 1. x-4y+z=-3 2x+y-z=18 x-y-z=7 2. x:y:z=2:3:5 x+y+z=100 要过程 谢谢 (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian x+y+z=14 7z=x+y+2 x+z=y x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)= (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z