设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值

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设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值

设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值
设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值

设A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y,若x-2a差的绝对值+(y+3)^2=0且B-2A=a,求A的值
因为x-2a差的绝对值+(y+3)^2=0.所以可列不等式组x-2a=0;y+3=0.解得x=2a;y=-3.
又因为B-2A=a,即2B-4A=2a,得x=2B-4A.
再将A=2x^2-3xy+y^3-x+2y,B=4x^2-6xy+2y^2+3x-y代入.得x=y^2*(y+1)+2x-10y
再将y=-3代入,得x=12-2x.解得x=4.
则A=31